What is 1000(1+(0.02)/4)^{(4*8)} ?

The solution to 1000(1+(0.02)/4)^{(4*8)} is (201^{32})/(5^{61)*8^{31}}

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simplify 1000(1+(0.02)/4)^{(4*8)}

simplify

1000 (1 + \frac{0.02}{4})^{(4 \cdot 8)}

\frac{20 1 ^{32}}{5 ^{61} \cdot 8 ^{31}}

Decimal Notation

1173.04311 \dots

Solution steps

1000 (1 + \frac{0.02}{4})^{4 \cdot 8}

Multiply the numbers:

4 \cdot 8 = 32

= 1000 (1 + \frac{0.02}{4})^{32}

Simplify

1 + \frac{0.02}{4} : \frac{201}{200}

= 1000 (\frac{201}{200})^{32}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{201}{200})^{32} = \frac{20 1 ^{32}}{20 0 ^{32}}

= 1000 \cdot \frac{20 1 ^{32}}{20 0 ^{32}}

1000 \cdot \frac{20 1 ^{32}}{20 0 ^{32}} = \frac{20 1 ^{32}}{5 ^{61} \cdot 8 ^{31}}

= \frac{20 1 ^{32}}{5 ^{61} \cdot 8 ^{31}}

5 x + 20 = 70

(5 + - 1) + (9 + - 49)

∣ u - 2 ∣ \leq 2

12 k \leq - 24

2 x^{2} - 5 x + 3 = 0

What is 1000(1+(0.02)/4)^{(4*8)} ?
The solution to 1000(1+(0.02)/4)^{(4*8)} is (201^{32})/(5^{61)*8^{31}}