What are the solutions to the equation 3x(x-3)=9x^2-14x ?

The solutions to the equation 3x(x-3)=9x^2-14x are x=0,x= 5/6

Find the zeros of 3x(x-3)=9x^2-14x

The zeros of 3x(x-3)=9x^2-14x are x=0,x= 5/6

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3 x (x - 3) = 9 x^{2} - 14 x

x = 0, x = \frac{5}{6}

Decimal Notation

x = 0, x = 0.83333 \dots

Solution steps

3 x (x - 3) = 9 x^{2} - 14 x

Expand

3 x (x - 3) : 3 x^{2} - 9 x

3 x^{2} - 9 x = 9 x^{2} - 14 x

Move

14 x

to the left side

3 x^{2} + 5 x = 9 x^{2}

Move

9 x^{2}

to the left side

- 6 x^{2} + 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 6 ) \cdot 0}{2 ( - 6 )}

5^{2} - 4 (- 6) \cdot 0 = 5

x_{1, 2} = \frac{- 5 \pm 5}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 5 + 5}{2 ( - 6 )}, x_{2} = \frac{- 5 - 5}{2 ( - 6 )}

x = \frac{- 5 + 5}{2 ( - 6 )} : 0

x = \frac{- 5 - 5}{2 ( - 6 )} : \frac{5}{6}

The solutions to the quadratic equation are:

x = 0, x = \frac{5}{6}

\frac{2}{3} - \frac{7}{9}

\frac{3}{4} \cdot \frac{2}{3}

11 x^{2} + 74 x + 48

x - 7 > 4

\frac{1}{1 0 ^{3}}

What are the solutions to the equation 3x(x-3)=9x^2-14x ?
The solutions to the equation 3x(x-3)=9x^2-14x are x=0,x= 5/6
Find the zeros of 3x(x-3)=9x^2-14x
The zeros of 3x(x-3)=9x^2-14x are x=0,x= 5/6