What is factor 3d^2+20d+12 ?

The solution to factor 3d^2+20d+12 is (3d+2)(d+6)

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factor 3d^2+20d+12

factor

3 d^{2} + 20 d + 12

(3 d + 2) (d + 6)

Solution steps

3 d^{2} + 20 d + 12

Break the expression into groups

= (3 d^{2} + 2 d) + (18 d + 12)

Factor out

d

from

3 d^{2} + 2 d : d (3 d + 2)

Factor out

6

from

18 d + 12 : 6 (3 d + 2)

= d (3 d + 2) + 6 (3 d + 2)

Factor out common term

3 d + 2

= (3 d + 2) (d + 6)

- 18 = - 3 t

- 5 > \frac{4 x - 16}{2} > - 17

4 (2)^{3}

x^{2} + 12 x - 8 = 0

x^{2} - 8 = 4 x - 12