What are the solutions to the equation 3(x+4)^2=60 ?

The solutions to the equation 3(x+4)^2=60 are x=2sqrt(5)-4,x=-2sqrt(5)-4

Find the zeros of 3(x+4)^2=60

The zeros of 3(x+4)^2=60 are x=2sqrt(5)-4,x=-2sqrt(5)-4

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3 (x + 4)^{2} = 60

x = 25 - 4, x = - 25 - 4

Decimal Notation

x = 0.47213 \dots, x = - 8.47213 \dots

Solution steps

3 (x + 4)^{2} = 60

Divide both sides by

3

(x + 4)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 20 : x = 25 - 4

Solve

x + 4 = - 20 : x = - 25 - 4

The solutions to the quadratic equation are:

x = 25 - 4, x = - 25 - 4

∣ - x + 5 ∣ \geq ∣ 2 x - 1 ∣

\frac{\frac{3}{5}}{2}

30 < 3 x - 3 (\frac{x - 10}{2}) \leq 60

115 = x e^{0.5 l n (\frac{65}{23}) \cdot 2}

(\frac{1}{2}) y + \frac{1}{2} + 1 = y - (\frac{1}{2})^{2}

What are the solutions to the equation 3(x+4)^2=60 ?
The solutions to the equation 3(x+4)^2=60 are x=2sqrt(5)-4,x=-2sqrt(5)-4
Find the zeros of 3(x+4)^2=60
The zeros of 3(x+4)^2=60 are x=2sqrt(5)-4,x=-2sqrt(5)-4