What is factor x^4-2x^3-3x^2+4x+4 ?

The solution to factor x^4-2x^3-3x^2+4x+4 is (x+1)^2(x-2)^2

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factor x^4-2x^3-3x^2+4x+4

factor

x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4

(x + 1)^{2} (x - 2)^{2}

Solution steps

x^{4} - 2 x^{3} - 3 x^{2} + 4 x + 4

Use the rational root theorem

= (x + 1) \frac{x ^{4} - 2 x ^{3} - 3 x ^{2} + 4 x + 4}{x + 1}

\frac{x ^{4} - 2 x ^{3} - 3 x ^{2} + 4 x + 4}{x + 1} = x^{3} - 3 x^{2} + 4

= (x + 1) (x^{3} - 3 x^{2} + 4)

Factor

x^{3} - 3 x^{2} + 4 : (x + 1) (x - 2) (x - 2)

= (x + 1) (x + 1) (x - 2) (x - 2)

Simplify

= (x + 1)^{2} (x - 2)^{2}

lo g_{2} (0.1)

4 n^{2} - 64

3 x \geq 2 x - 10

2 x^{2} - 1 x - 2 = 0

What is factor x^4-2x^3-3x^2+4x+4 ?
The solution to factor x^4-2x^3-3x^2+4x+4 is (x+1)^2(x-2)^2