What are the solutions to the equation x^2-12x+5=0 ?

The solutions to the equation x^2-12x+5=0 are x=6+sqrt(31),x=6-sqrt(31)

Find the zeros of x^2-12x+5=0

The zeros of x^2-12x+5=0 are x=6+sqrt(31),x=6-sqrt(31)

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x^{2} - 12 x + 5 = 0

x = 6 + 31, x = 6 - 31

Decimal Notation

x = 11.56776 \dots, x = 0.43223 \dots

Solution steps

x^{2} - 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 5 = 231

x_{1, 2} = \frac{- ( - 12 ) \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 31}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 31}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 31}{2 \cdot 1} : 6 + 31

x = \frac{- ( - 12 ) - 2 31}{2 \cdot 1} : 6 - 31

The solutions to the quadratic equation are:

x = 6 + 31, x = 6 - 31

3 z^{2} + 20 z - 7

345 + 20

(1 6^{3})^{\frac{1}{4}}

ln (e^{3})

2 s^{3} + 3 s^{2} - 3 s - 2

What are the solutions to the equation x^2-12x+5=0 ?
The solutions to the equation x^2-12x+5=0 are x=6+sqrt(31),x=6-sqrt(31)
Find the zeros of x^2-12x+5=0
The zeros of x^2-12x+5=0 are x=6+sqrt(31),x=6-sqrt(31)