What is -x^2>= 4-5x ?

The solution to -x^2>= 4-5x is 1<= x<= 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-x^2>= 4-5x

- x^{2} \geq 4 - 5 x

1 \leq x \leq 4

Interval Notation

[1, 4]

Solution steps

- x^{2} \geq 4 - 5 x

Rewrite in standard form

- x^{2} + 5 x - 4 \geq 0

Factor

- x^{2} + 5 x - 4 : - (x - 1) (x - 4)

- (x - 1) (x - 4) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 1) (x - 4)) (- 1) \leq 0 \cdot (- 1)

Simplify

(x - 1) (x - 4) \leq 0

Identify the intervals

1 \leq x \leq 4

4 x^{2} + 13 x = - 9

i^{233}

(1 + i) (2 + i) (3 + i)

x^{2} + 2 x - 35 > 0

\frac{n - 7}{2} + \frac{n + 5}{2}