What is the answer to -4a^2-12a+40=-4(a+5)(a-2) ?

The answer to -4a^2-12a+40=-4(a+5)(a-2) is True for all a

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-4a^2-12a+40=-4(a+5)(a-2)

- 4 a^{2} - 12 a + 40 = - 4 (a + 5) (a - 2)

True for all a

Solution steps

- 4 a^{2} - 12 a + 40 = - 4 (a + 5) (a - 2)

Expand

(a + 5) (a - 2) : a^{2} + 3 a - 10

- 4 a^{2} - 12 a + 40 = - 4 (a^{2} + 3 a - 10)

Expand

- 4 (a^{2} + 3 a - 10) : - 4 a^{2} - 12 a + 40

- 4 a^{2} - 12 a + 40 = - 4 a^{2} - 12 a + 40

Move

40

to the right side

- 4 a^{2} - 12 a = - 4 a^{2} - 12 a

Subtract

- 4 a^{2} - 12 a

from both sides

- 4 a^{2} - 12 a - (- 4 a^{2} - 12 a) = - 4 a^{2} - 12 a - (- 4 a^{2} - 12 a)

Simplify

0 = 0

Both sides are equal

True for all a

- 2 x \leq \frac{- 3 ( x + 1 )}{2}

- 8 h^{2} - 13 h + 6

∣ x - 4 ∣ = 9

3 (\frac{2}{3} x + \frac{1}{6}) - \frac{3}{4} (2 x + 18) = - 4

(k^{4})^{- 3}

What is the answer to -4a^2-12a+40=-4(a+5)(a-2) ?
The answer to -4a^2-12a+40=-4(a+5)(a-2) is True for all a
Solve for a: -4a^2-12a+40=-4(a+5)(a-2)
The solution is True for all a