What are the solutions to the equation x^2+12x+5=0 ?

The solutions to the equation x^2+12x+5=0 are x=-6+sqrt(31),x=-6-sqrt(31)

Find the zeros of x^2+12x+5=0

The zeros of x^2+12x+5=0 are x=-6+sqrt(31),x=-6-sqrt(31)

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x^{2} + 12 x + 5 = 0

x = - 6 + 31, x = - 6 - 31

Decimal Notation

x = - 0.43223 \dots, x = - 11.56776 \dots

Solution steps

x^{2} + 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 5 = 231

x_{1, 2} = \frac{- 12 \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 31}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 31}{2 \cdot 1}

x = \frac{- 12 + 2 31}{2 \cdot 1} : - 6 + 31

x = \frac{- 12 - 2 31}{2 \cdot 1} : - 6 - 31

The solutions to the quadratic equation are:

x = - 6 + 31, x = - 6 - 31

\frac{x ^{2} + 7 x}{x ^{3} - 5 x ^{2} - 14 x}

(w^{2})^{\frac{5}{14}}

- 3 x - 9 = x - 1

2 y^{2} + 7 y - 15

\frac{6 x ^{4} y ^{3}}{12 x y}

What are the solutions to the equation x^2+12x+5=0 ?
The solutions to the equation x^2+12x+5=0 are x=-6+sqrt(31),x=-6-sqrt(31)
Find the zeros of x^2+12x+5=0
The zeros of x^2+12x+5=0 are x=-6+sqrt(31),x=-6-sqrt(31)