What are the solutions to the equation -x^2+8x=0 ?

The solutions to the equation -x^2+8x=0 are x=0,x=8

Find the zeros of -x^2+8x=0

The zeros of -x^2+8x=0 are x=0,x=8

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- x^{2} + 8 x = 0

x = 0, x = 8

Solution steps

- x^{2} + 8 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 0 = 8

x_{1, 2} = \frac{- 8 \pm 8}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 8}{2 ( - 1 )}, x_{2} = \frac{- 8 - 8}{2 ( - 1 )}

x = \frac{- 8 + 8}{2 ( - 1 )} : 0

x = \frac{- 8 - 8}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

x = 0, x = 8

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What are the solutions to the equation -x^2+8x=0 ?
The solutions to the equation -x^2+8x=0 are x=0,x=8
Find the zeros of -x^2+8x=0
The zeros of -x^2+8x=0 are x=0,x=8