What are the solutions to the equation 3m^2-1=0 ?

The solutions to the equation 3m^2-1=0 are m= 1/(sqrt(3)),m=-1/(sqrt(3))

Find the zeros of 3m^2-1=0

The zeros of 3m^2-1=0 are m= 1/(sqrt(3)),m=-1/(sqrt(3))

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3 m^{2} - 1 = 0

m = \frac{1}{3}, m = - \frac{1}{3}

Decimal Notation

m = 0.57735 \dots, m = - 0.57735 \dots

Solution steps

3 m^{2} - 1 = 0

Move

1

to the right side

3 m^{2} = 1

Divide both sides by

3

m^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{1}{3}, m = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

m = \frac{1}{3}, m = - \frac{1}{3}

2 x^{2} + 3 x + 5 = 0

x^{2} - 6 x + 10 = 0

\frac{3 x - 4}{3} = 5 x + 7

(2 x - 3) (2 x + 3) \geq 0

x^{2} + 22 x + 40

What are the solutions to the equation 3m^2-1=0 ?
The solutions to the equation 3m^2-1=0 are m= 1/(sqrt(3)),m=-1/(sqrt(3))
Find the zeros of 3m^2-1=0
The zeros of 3m^2-1=0 are m= 1/(sqrt(3)),m=-1/(sqrt(3))