What are the solutions to the equation -10x=-25-x^2 ?

The solutions to the equation -10x=-25-x^2 are x=5

Find the zeros of -10x=-25-x^2

The zeros of -10x=-25-x^2 are x=5

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- 10 x = - 25 - x^{2}

x = 5

Solution steps

- 10 x = - 25 - x^{2}

Switch sides

- 25 - x^{2} = - 10 x

Move

10 x

to the left side

- 25 - x^{2} + 10 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 25 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 25) = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 ( - 1 )}

x = \frac{- 10}{2 ( - 1 )}

\frac{- 10}{2 ( - 1 )} = 5

x = 5

The solution to the quadratic equation is:

x = 5

2 p^{2} + p

\frac{( 1.15 \cdot 1 0 ^{- 3} )}{( 8.92 \cdot 1 0 ^{3} )}

5 x^{2} - 15 x + 4 x - 12

0.6 x + 0.85 (x - 0.8) = 120

\frac{e}{4} = 2.5

What are the solutions to the equation -10x=-25-x^2 ?
The solutions to the equation -10x=-25-x^2 are x=5
Find the zeros of -10x=-25-x^2
The zeros of -10x=-25-x^2 are x=5