What is (x^2+11x-4)/(5x+1)<= 2 ?

The solution to (x^2+11x-4)/(5x+1)<= 2 is x<=-3\lor-1/5 <x<= 2

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(x^2+11x-4)/(5x+1)<= 2

\frac{x ^{2} + 11 x - 4}{5 x + 1} \leq 2

x \leq - 3 or - \frac{1}{5} < x \leq 2

Interval Notation

(- \infty, - 3] \cup (- \frac{1}{5}, 2]

Decimal Notation

x \leq - 3 or - 0.2 < x \leq 2

Solution steps

\frac{x ^{2} + 11 x - 4}{5 x + 1} \leq 2

Rewrite in standard form

\frac{x ^{2} + x - 6}{5 x + 1} \leq 0

Factor

\frac{x ^{2} + x - 6}{5 x + 1} : \frac{( x - 2 ) ( x + 3 )}{5 x + 1}

\frac{( x - 2 ) ( x + 3 )}{5 x + 1} \leq 0

Identify the intervals

x \leq - 3 or - \frac{1}{5} < x \leq 2

t^{2} = 28 - 3 t

7 x^{2} - 9 x + 2

(9 x - 1)^{2} = 1

(9 x + 59) + (6 x + 16) = 180

(0.1 70)^{2} + 1.69

What is (x^2+11x-4)/(5x+1)<= 2 ?
The solution to (x^2+11x-4)/(5x+1)<= 2 is x<=-3\lor-1/5 <x<= 2