What are the solutions to the equation (x+4)^2=25 ?

The solutions to the equation (x+4)^2=25 are x=1,x=-9

Find the zeros of (x+4)^2=25

The zeros of (x+4)^2=25 are x=1,x=-9

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(x + 4)^{2} = 25

x = 1, x = - 9

Solution steps

(x + 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 25 : x = 1

Solve

x + 4 = - 25 : x = - 9

The solutions to the quadratic equation are:

x = 1, x = - 9

2 x^{3} - 8 x^{2} + 2 x + 12

- 3 a \leq - 24 or a + 8 \leq 11

\frac{x ^{2} - 7 x + 6}{x + 3} \leq 0

2 (x - 3) (2 x + 1)^{4} + 4 (x - 3)^{2} (2 x + 1)^{3}

\frac{x ^{4}}{x ^{5}}

What are the solutions to the equation (x+4)^2=25 ?
The solutions to the equation (x+4)^2=25 are x=1,x=-9
Find the zeros of (x+4)^2=25
The zeros of (x+4)^2=25 are x=1,x=-9