What are the solutions to the equation k^2=4 ?

The solutions to the equation k^2=4 are k=2,k=-2

Find the zeros of k^2=4

The zeros of k^2=4 are k=2,k=-2

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k^{2} = 4

k = 2, k = - 2

Solution steps

k^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 4, k = - 4

4 = 2

- 4 = - 2

k = 2, k = - 2

- \frac{7 x y}{3 x} + \frac{4 y ^{2}}{2 y}

\frac{2 ( - 0.501 ) + 1}{\frac{1}{4} - ( - 0.50 1 ^{2} )}

\frac{1}{2} z = 9

- 20 u - 25 v - 35 w

5 (2 x - 3) + 8 = 9

What are the solutions to the equation k^2=4 ?
The solutions to the equation k^2=4 are k=2,k=-2
Find the zeros of k^2=4
The zeros of k^2=4 are k=2,k=-2