What is ((1/3-i/6))/((2/3-i/3)) ?

The solution to ((1/3-i/6))/((2/3-i/3)) is 1/2

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simplify ((1/3-i/6))/((2/3-i/3))

simplify

\frac{( \frac{1}{3} - \frac{i}{6} )}{( \frac{2}{3} - \frac{i}{3} )}

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\frac{\frac{1}{3} - \frac{i}{6}}{\frac{2}{3} - \frac{i}{3}}

Rewrite

\frac{1}{3} - \frac{i}{6}

in standard complex form:

\frac{1}{3} - \frac{1}{6} i

Rewrite

\frac{2}{3} - \frac{i}{3}

in standard complex form:

\frac{2}{3} - \frac{1}{3} i

= \frac{\frac{1}{3} - \frac{1}{6} i}{\frac{2}{3} - \frac{1}{3} i}

Multiply by the conjugate

\frac{\frac{2}{3} + \frac{1}{3} i}{\frac{2}{3} + \frac{1}{3} i}

= \frac{( \frac{1}{3} - \frac{1}{6} i ) ( \frac{2}{3} + \frac{1}{3} i )}{( \frac{2}{3} - \frac{1}{3} i ) ( \frac{2}{3} + \frac{1}{3} i )}

Simplify

\frac{( \frac{1}{3} - \frac{1}{6} i ) ( \frac{2}{3} + \frac{1}{3} i )}{( \frac{2}{3} - \frac{1}{3} i ) ( \frac{2}{3} + \frac{1}{3} i )} : \frac{\frac{5}{18}}{\frac{5}{9}}

= \frac{\frac{5}{18}}{\frac{5}{9}}

\frac{\frac{5}{18}}{\frac{5}{9}} = \frac{1}{2}

= \frac{1}{2}

- 4 x \leq - 16

7 x - 1 = 8 x - 14

10 x - 4.5 + 3 x = 12 x - 1.1

ln (e^{x})

12 x^{2} + x - 1

What is ((1/3-i/6))/((2/3-i/3)) ?
The solution to ((1/3-i/6))/((2/3-i/3)) is 1/2