What is the answer to x^2-3x=(x+3)(x-4) ?

The answer to x^2-3x=(x+3)(x-4) is x=6

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x^2-3x=(x+3)(x-4)

x^{2} - 3 x = (x + 3) (x - 4)

x = 6

Solution steps

x^{2} - 3 x = (x + 3) (x - 4)

Expand

(x + 3) (x - 4) : x^{2} - x - 12

x^{2} - 3 x = x^{2} - x - 12

Subtract

x^{2} - x

from both sides

x^{2} - 3 x - (x^{2} - x) = x^{2} - x - 12 - (x^{2} - x)

Simplify

- 2 x = - 12

Divide both sides by

- 2

x = 6

∣ x - 6 ∣ > 7

- x + 3 \geq 1 or 6 x + 4 < - 3

lo g_{b} (4)

6 n^{2} - 35 n + 25

x^{2} - 0.74 x + 0.062 = 0

What is the answer to x^2-3x=(x+3)(x-4) ?
The answer to x^2-3x=(x+3)(x-4) is x=6
Solve for x: x^2-3x=(x+3)(x-4)
The solution is x=6