What is (x^2-4x-21)/(x+8)>= 0 ?

The solution to (x^2-4x-21)/(x+8)>= 0 is -8 = 7

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(x^2-4x-21)/(x+8)>= 0

\frac{x ^{2} - 4 x - 21}{x + 8} \geq 0

- 8 < x \leq - 3 or x \geq 7

Interval Notation

(- 8, - 3] \cup [7, \infty)

Solution steps

\frac{x ^{2} - 4 x - 21}{x + 8} \geq 0

Factor

\frac{x ^{2} - 4 x - 21}{x + 8} : \frac{( x + 3 ) ( x - 7 )}{x + 8}

\frac{( x + 3 ) ( x - 7 )}{x + 8} \geq 0

Identify the intervals

- 8 < x \leq - 3 or x \geq 7

(25 x)^{\frac{3}{2}}

(x^{3})^{8}

7 x^{2} + 21 x + 7

x^{6} + 2 x^{3} + 1

\frac{x + 5}{4} = \frac{- 15}{6}

What is (x^2-4x-21)/(x+8)>= 0 ?
The solution to (x^2-4x-21)/(x+8)>= 0 is -8<x<=-3\lor x>= 7