What are the solutions to the equation 2x^2-x+8=0 ?

The solutions to the equation 2x^2-x+8=0 are x= 1/4+i(3sqrt(7))/4 ,x= 1/4-i(3sqrt(7))/4

Find the zeros of 2x^2-x+8=0

The zeros of 2x^2-x+8=0 are x= 1/4+i(3sqrt(7))/4 ,x= 1/4-i(3sqrt(7))/4

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2 x^{2} - x + 8 = 0

x = \frac{1}{4} + i \frac{3 7}{4}, x = \frac{1}{4} - i \frac{3 7}{4}

Solution steps

2 x^{2} - x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 8 : 37 i

x_{1, 2} = \frac{- ( - 1 ) \pm 3 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3 7 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 3 7 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 3 7 i}{2 \cdot 2} : \frac{1}{4} + i \frac{3 7}{4}

x = \frac{- ( - 1 ) - 3 7 i}{2 \cdot 2} : \frac{1}{4} - i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{3 7}{4}, x = \frac{1}{4} - i \frac{3 7}{4}

- \frac{6}{7} - 1

80000 \cdot \frac{1}{( 1 + 0.06 ) ^{30}}

- 16 t^{2} - 8 t + 64

\frac{4}{11}

\frac{4 b ^{- 8}}{( - 3 b ^{5} ) ^{5}}

What are the solutions to the equation 2x^2-x+8=0 ?
The solutions to the equation 2x^2-x+8=0 are x= 1/4+i(3sqrt(7))/4 ,x= 1/4-i(3sqrt(7))/4
Find the zeros of 2x^2-x+8=0
The zeros of 2x^2-x+8=0 are x= 1/4+i(3sqrt(7))/4 ,x= 1/4-i(3sqrt(7))/4