What are the solutions to the equation y^2-9y+14=0 ?

The solutions to the equation y^2-9y+14=0 are y=7,y=2

Find the zeros of y^2-9y+14=0

The zeros of y^2-9y+14=0 are y=7,y=2

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y^{2} - 9 y + 14 = 0

y = 7, y = 2

Solution steps

y^{2} - 9 y + 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

y_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, y_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

y = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

y = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

y = 7, y = 2

7 (x - 3) = 7

3 x^{3} + 3 x^{2} - 27 x - 27

- \frac{1}{4} (3 x - \frac{1}{2}) > 0

- 7 x + 8 - 10 x^{2} = 7

4 u^{2} + 28 u = 0

What are the solutions to the equation y^2-9y+14=0 ?
The solutions to the equation y^2-9y+14=0 are y=7,y=2
Find the zeros of y^2-9y+14=0
The zeros of y^2-9y+14=0 are y=7,y=2