What are the solutions to the equation x^2-2=0 ?

The solutions to the equation x^2-2=0 are x=sqrt(2),x=-sqrt(2)

Find the zeros of x^2-2=0

The zeros of x^2-2=0 are x=sqrt(2),x=-sqrt(2)

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x^{2} - 2 = 0

x = 2, x = - 2

Solution steps

x^{2} - 2 = 0

Move

2

to the right side

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

(\frac{9 ^{3}}{6 ^{3}})^{- \frac{1}{3}}

a^{3} - a^{2} x + a x^{2}

4 x^{2} - 28 x + 49 \leq 0

- 6 x - 2 (x - 5) = 4

12 5^{\frac{1}{3}} + 1 6^{\frac{1}{2}}

What are the solutions to the equation x^2-2=0 ?
The solutions to the equation x^2-2=0 are x=sqrt(2),x=-sqrt(2)
Find the zeros of x^2-2=0
The zeros of x^2-2=0 are x=sqrt(2),x=-sqrt(2)