What are the solutions to the equation 2(x-1)^2+24=0 ?

The solutions to the equation 2(x-1)^2+24=0 are x=2sqrt(3)i+1,x=-2sqrt(3)i+1

Find the zeros of 2(x-1)^2+24=0

The zeros of 2(x-1)^2+24=0 are x=2sqrt(3)i+1,x=-2sqrt(3)i+1

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2 (x - 1)^{2} + 24 = 0

x = 23 i + 1, x = - 23 i + 1

Solution steps

2 (x - 1)^{2} + 24 = 0

Move

24

to the right side

2 (x - 1)^{2} = - 24

Divide both sides by

2

(x - 1)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = - 12 : x = 23 i + 1

Solve

x - 1 = - - 12 : x = - 23 i + 1

The solutions to the quadratic equation are:

x = 23 i + 1, x = - 23 i + 1

b - 1 < - 11

lo g_{7} (9)

- 2 ∣ 6 v + 10 ∣ = - 22

n^{3} - n^{2}

5 x + 3 = 2 x + 9

What are the solutions to the equation 2(x-1)^2+24=0 ?
The solutions to the equation 2(x-1)^2+24=0 are x=2sqrt(3)i+1,x=-2sqrt(3)i+1
Find the zeros of 2(x-1)^2+24=0
The zeros of 2(x-1)^2+24=0 are x=2sqrt(3)i+1,x=-2sqrt(3)i+1