What are the solutions to the equation 49s^2-14s+1=0 ?

The solutions to the equation 49s^2-14s+1=0 are s= 1/7

Find the zeros of 49s^2-14s+1=0

The zeros of 49s^2-14s+1=0 are s= 1/7

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49 s^{2} - 14 s + 1 = 0

s = \frac{1}{7}

Solution steps

49 s^{2} - 14 s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 49 \cdot 1}{2 \cdot 49}

(- 14)^{2} - 4 \cdot 49 \cdot 1 = 0

s_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 49}

s = \frac{- ( - 14 )}{2 \cdot 49}

\frac{- ( - 14 )}{2 \cdot 49} = \frac{1}{7}

s = \frac{1}{7}

The solution to the quadratic equation is:

s = \frac{1}{7}

2 p^{2} + 9 p - 11

7 m + 7 = - 6 m + 2

g (- 3) = 4 - 3 (- 3)

1 6^{\frac{3}{2}}

∣ 3 x + 8 ∣ = ∣ x - 17 ∣

What are the solutions to the equation 49s^2-14s+1=0 ?
The solutions to the equation 49s^2-14s+1=0 are s= 1/7
Find the zeros of 49s^2-14s+1=0
The zeros of 49s^2-14s+1=0 are s= 1/7