What are the solutions to the equation 2x^2+4=396 ?

The solutions to the equation 2x^2+4=396 are x=14,x=-14

Find the zeros of 2x^2+4=396

The zeros of 2x^2+4=396 are x=14,x=-14

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2 x^{2} + 4 = 396

x = 14, x = - 14

Solution steps

2 x^{2} + 4 = 396

Move

4

to the right side

2 x^{2} = 392

Divide both sides by

2

x^{2} = 196

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 196, x = - 196

196 = 14

- 196 = - 14

x = 14, x = - 14

\frac{3}{4} \cdot \frac{8}{5} \cdot \frac{4}{9}

- x^{2} + 4 x - 3 = 0

- 3 x > 18

y^{2} - y - 30

- \frac{18}{- 3}

What are the solutions to the equation 2x^2+4=396 ?
The solutions to the equation 2x^2+4=396 are x=14,x=-14
Find the zeros of 2x^2+4=396
The zeros of 2x^2+4=396 are x=14,x=-14