What are the solutions to the equation 2w^2-11w+8=0 ?

The solutions to the equation 2w^2-11w+8=0 are w=(11+sqrt(57))/4 ,w=(11-sqrt(57))/4

Find the zeros of 2w^2-11w+8=0

The zeros of 2w^2-11w+8=0 are w=(11+sqrt(57))/4 ,w=(11-sqrt(57))/4

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2 w^{2} - 11 w + 8 = 0

w = \frac{11 + 57}{4}, w = \frac{11 - 57}{4}

Solution steps

2 w^{2} - 11 w + 8 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 8 = 57

w_{1, 2} = \frac{- ( - 11 ) \pm 57}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 11 ) + 57}{2 \cdot 2}, w_{2} = \frac{- ( - 11 ) - 57}{2 \cdot 2}

w = \frac{- ( - 11 ) + 57}{2 \cdot 2} : \frac{11 + 57}{4}

w = \frac{- ( - 11 ) - 57}{2 \cdot 2} : \frac{11 - 57}{4}

The solutions to the quadratic equation are:

w = \frac{11 + 57}{4}, w = \frac{11 - 57}{4}

16 + 40 x + 25 x^{2}

4 x^{2} + 17 x + 14 = 0

- 3 + 3 x^{5}

5 x = 3 x - 10 + 2 x

- 2 y = - 8

What are the solutions to the equation 2w^2-11w+8=0 ?
The solutions to the equation 2w^2-11w+8=0 are w=(11+sqrt(57))/4 ,w=(11-sqrt(57))/4
Find the zeros of 2w^2-11w+8=0
The zeros of 2w^2-11w+8=0 are w=(11+sqrt(57))/4 ,w=(11-sqrt(57))/4