What is (3/12+7/8 (3/4+2/3))/((-1/2)^3) ?

The solution to (3/12+7/8 (3/4+2/3))/((-1/2)^3) is -143/12

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simplify (3/12+7/8 (3/4+2/3))/((-1/2)^3)

simplify

\frac{\frac{3}{12} + \frac{7}{8} ( \frac{3}{4} + \frac{2}{3} )}{( - \frac{1}{2} ) ^{3}}

- \frac{143}{12}

Decimal Notation

- 11.91666 \dots

Solution steps

\frac{\frac{3}{12} + \frac{7}{8} ( \frac{3}{4} + \frac{2}{3} )}{( - \frac{1}{2} ) ^{3}}

\frac{3}{12} + \frac{7}{8} (\frac{3}{4} + \frac{2}{3}) = \frac{143}{96}

= \frac{\frac{143}{96}}{( - \frac{1}{2} ) ^{3}}

(- \frac{1}{2})^{3} = - \frac{1}{8}

= \frac{\frac{143}{96}}{- \frac{1}{8}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{143}{96}}{\frac{1}{8}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

\frac{\frac{143}{96}}{\frac{1}{8}} = \frac{143 \cdot 8}{96 \cdot 1}

= - \frac{143 \cdot 8}{96 \cdot 1}

Cancel

- \frac{143 \cdot 8}{96 \cdot 1} : - \frac{143}{12}

= - \frac{143}{12}

12 \div 4

6 x^{2} - 6 - 5 x

(b - 6)^{3}

- x \cdot x

\frac{16}{9}

What is (3/12+7/8 (3/4+2/3))/((-1/2)^3) ?
The solution to (3/12+7/8 (3/4+2/3))/((-1/2)^3) is -143/12