What are the solutions to the equation x^2-3x-2=0 ?

The solutions to the equation x^2-3x-2=0 are x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2

Find the zeros of x^2-3x-2=0

The zeros of x^2-3x-2=0 are x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2

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x^{2} - 3 x - 2 = 0

x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

Solution steps

x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 2) = 17

x_{1, 2} = \frac{- ( - 3 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 17}{2 \cdot 1}

x = \frac{- ( - 3 ) + 17}{2 \cdot 1} : \frac{3 + 17}{2}

x = \frac{- ( - 3 ) - 17}{2 \cdot 1} : \frac{3 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

23 x + 5 > - 110

3 x + 5 = 11

- 6 w + 12 > 48

p^{2} = - 11

n - 12 = 3 n

What are the solutions to the equation x^2-3x-2=0 ?
The solutions to the equation x^2-3x-2=0 are x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2
Find the zeros of x^2-3x-2=0
The zeros of x^2-3x-2=0 are x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2