What is expand (x^2-2x-4)(x^2-3x-5) ?

The solution to expand (x^2-2x-4)(x^2-3x-5) is x^4-5x^3-3x^2+22x+20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^2-2x-4)(x^2-3x-5)

expand

(x^{2} - 2 x - 4) (x^{2} - 3 x - 5)

x^{4} - 5 x^{3} - 3 x^{2} + 22 x + 20

Solution steps

(x^{2} - 2 x - 4) (x^{2} - 3 x - 5)

Distribute parentheses

= x^{2} x^{2} + x^{2} (- 3 x) + x^{2} (- 5) - 2 x x^{2} - 2 x (- 3 x) - 2 x (- 5) - 4 x^{2} - 4 (- 3 x) - 4 (- 5)

Simplify

x^{2} x^{2} + x^{2} (- 3 x) + x^{2} (- 5) - 2 x x^{2} - 2 x (- 3 x) - 2 x (- 5) - 4 x^{2} - 4 (- 3 x) - 4 (- 5) : x^{4} - 5 x^{3} - 3 x^{2} + 22 x + 20

= x^{4} - 5 x^{3} - 3 x^{2} + 22 x + 20

\frac{15}{36}

\frac{18}{6}

\frac{4 x}{x}

- lo g_{10} (0.001)

lo g_{7} (\frac{8}{81})

What is expand (x^2-2x-4)(x^2-3x-5) ?
The solution to expand (x^2-2x-4)(x^2-3x-5) is x^4-5x^3-3x^2+22x+20