What is 4^{log_{2}(5)-log_{8}(27)} ?

The solution to 4^{log_{2}(5)-log_{8}(27)} is 25/9

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simplify 4^{log_{2}(5)-log_{8}(27)}

simplify

4^{l o g_{2} (5) - l o g_{8} (27)}

\frac{25}{9}

Decimal Notation

2.77777 \dots

Solution steps

4^{l o g_{2} (5) - l o g_{8} (27)}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

4^{l o g_{2} (5) - l o g_{8} (27)} = 4^{l o g_{2} (5)} \cdot 4^{- l o g_{8} (27)}

= 4^{l o g_{2} (5)} \cdot 4^{- l o g_{8} (27)}

4^{l o g_{2} (5)} = 25

4^{- l o g_{8} (27)} = \frac{1}{9}

= 25 \cdot \frac{1}{9}

25 \cdot \frac{1}{9} = \frac{25}{9}

= \frac{25}{9}

(x - 5) (x - 7)

3 \times 4

1.17 - 0.07 a + (- 3.92 a)

\frac{2}{5 a ^{2}} + \frac{1}{3 ab}

lo g_{10} (10000000)

What is 4^{log_{2}(5)-log_{8}(27)} ?
The solution to 4^{log_{2}(5)-log_{8}(27)} is 25/9