What is factor 16c^2-104c+169 ?

The solution to factor 16c^2-104c+169 is (4c-13)^2

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factor 16c^2-104c+169

factor

16 c^{2} - 104 c + 169

(4 c - 13)^{2}

Solution steps

16 c^{2} - 104 c + 169

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 c^{2} = (4 c)^{2}

169 = 1 3^{2}

- 104 c = - 2 \cdot 4 c \cdot 13

= (4 c)^{2} - 2 \cdot 4 c \cdot 13 + 1 3^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(4 c)^{2} - 2 \cdot 4 c \cdot 13 + 1 3^{2} = (4 c - 13)^{2}

= (4 c - 13)^{2}

\frac{1}{x} d x

- 4^{4}

(- 14) \times 5

\frac{30}{100}

3 (x + 4)

What is factor 16c^2-104c+169 ?
The solution to factor 16c^2-104c+169 is (4c-13)^2