What are the solutions to the equation 3x(x-2)=6x^2-7x ?

The solutions to the equation 3x(x-2)=6x^2-7x are x=0,x= 1/3

Find the zeros of 3x(x-2)=6x^2-7x

The zeros of 3x(x-2)=6x^2-7x are x=0,x= 1/3

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3 x (x - 2) = 6 x^{2} - 7 x

x = 0, x = \frac{1}{3}

Decimal Notation

x = 0, x = 0.33333 \dots

Solution steps

3 x (x - 2) = 6 x^{2} - 7 x

Expand

3 x (x - 2) : 3 x^{2} - 6 x

3 x^{2} - 6 x = 6 x^{2} - 7 x

Move

7 x

to the left side

3 x^{2} + x = 6 x^{2}

Move

6 x^{2}

to the left side

- 3 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

1^{2} - 4 (- 3) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 3 )}, x_{2} = \frac{- 1 - 1}{2 ( - 3 )}

x = \frac{- 1 + 1}{2 ( - 3 )} : 0

x = \frac{- 1 - 1}{2 ( - 3 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{3}

80 a^{5} b^{15}

16 c^{2} - 28 c + 9 = - 4 c

(\frac{1}{9})^{- \frac{3}{2}}

(x - 1) (x + 2) (x + 3) > (x + 2) (x - 3)

- 10 < 2 + 2 x < 10

What are the solutions to the equation 3x(x-2)=6x^2-7x ?
The solutions to the equation 3x(x-2)=6x^2-7x are x=0,x= 1/3
Find the zeros of 3x(x-2)=6x^2-7x
The zeros of 3x(x-2)=6x^2-7x are x=0,x= 1/3