What is (x^2+10x+24)/(x^2-x-20) ?

The solution to (x^2+10x+24)/(x^2-x-20) is (x+6)/(x-5)

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simplify (x^2+10x+24)/(x^2-x-20)

simplify

\frac{x ^{2} + 10 x + 24}{x ^{2} - x - 20}

\frac{x + 6}{x - 5}

Solution steps

\frac{x ^{2} + 10 x + 24}{x ^{2} - x - 20}

Factor

x^{2} + 10 x + 24 : (x + 4) (x + 6)

= \frac{( x + 4 ) ( x + 6 )}{x ^{2} - x - 20}

Factor

x^{2} - x - 20 : (x + 4) (x - 5)

= \frac{( x + 4 ) ( x + 6 )}{( x + 4 ) ( x - 5 )}

Cancel the common factor:

x + 4

= \frac{x + 6}{x - 5}

2 x \cdot 3 x

(x + y + z)^{3}

(x - 3) (x + 6)

\frac{x + 1}{x ^{2} - 1}

(x - 1) (x + 5)

What is (x^2+10x+24)/(x^2-x-20) ?
The solution to (x^2+10x+24)/(x^2-x-20) is (x+6)/(x-5)