What is expand (x^3-3y^a)^2 ?

The solution to expand (x^3-3y^a)^2 is x^6-6x^3y^a+9y^{2a}

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expand (x^3-3y^a)^2

expand

(x^{3} - 3 y^{a})^{2}

x^{6} - 6 x^{3} y^{a} + 9 y^{2 a}

Solution steps

(x^{3} - 3 y^{a})^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(x^{3} - 3 y^{a})^{2} = (x^{3})^{2} - 2 x^{3} \cdot 3 y^{a} + (3 y^{a})^{2}

= (x^{3})^{2} - 2 x^{3} \cdot 3 y^{a} + (3 y^{a})^{2}

Simplify

(x^{3})^{2} - 2 x^{3} \cdot 3 y^{a} + (3 y^{a})^{2} : x^{6} - 6 x^{3} y^{a} + 9 y^{2 a}

= x^{6} - 6 x^{3} y^{a} + 9 y^{2 a}

1 - \frac{cos ^{2} ( x )}{1 + sin ( x )}

(3 x^{3} - 2 x^{2} + 4 x - 8) - (5 x^{3} + 12 x^{2} - 3 x - 4)

ln (e^{x^{2}})

(3 x + 7)^{2}

(x + 3) (x - 6)

What is expand (x^3-3y^a)^2 ?
The solution to expand (x^3-3y^a)^2 is x^6-6x^3y^a+9y^{2a}