What is log_{28}(7)+log_{28}(4) ?

The solution to log_{28}(7)+log_{28}(4) is 1

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simplify log_{28}(7)+log_{28}(4)

simplify

lo g_{28} (7) + lo g_{28} (4)

1

Solution steps

lo g_{28} (7) + lo g_{28} (4)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{28} (7) + lo g_{28} (4) = lo g_{28} (7 \cdot 4)

= lo g_{28} (7 \cdot 4)

Multiply the numbers:

7 \cdot 4 = 28

= lo g_{28} (28)

Apply log rule:

lo g_{a} (a) = 1

= 1

(6 x - 1)^{3}

(- 4) (- 5 x^{2})

6 \times 7

1 \frac{1}{5}

- 3 \times 2