What is factor 27a^6-(a-b)^3 ?

The solution to factor 27a^6-(a-b)^3 is (3a^2-a+b)(9a^4+3a^2(a-b)+(a-b)^2)

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factor 27a^6-(a-b)^3

factor

27 a^{6} - (a - b)^{3}

(3 a^{2} - a + b) (9 a^{4} + 3 a^{2} (a - b) + (a - b)^{2})

Solution steps

27 a^{6} - (a - b)^{3}

Rewrite

27 a^{6} - (a - b)^{3}

(3 a^{2})^{3} - (a - b)^{3}

= (3 a^{2})^{3} - (a - b)^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(3 a^{2})^{3} - (a - b)^{3} = (3 a^{2} - (a - b)) (3^{2} a^{4} + 3 a^{2} (a - b) + (a - b)^{2})

= (3 a^{2} - (a - b)) (3^{2} a^{4} + 3 a^{2} (a - b) + (a - b)^{2})

Refine

= (3 a^{2} - a + b) (9 a^{4} + 3 a^{2} (a - b) + (a - b)^{2})

4 p + 3 > 9 p + 6 - 5 p

2 \cdot 22

- 2 = \frac{x - 21.4}{5.1}

\frac{x}{3} + 2 = 15

\frac{2}{5} + 2

What is factor 27a^6-(a-b)^3 ?
The solution to factor 27a^6-(a-b)^3 is (3a^2-a+b)(9a^4+3a^2(a-b)+(a-b)^2)