What is (x+3)/4*(x+2)/(x^2+4x+3) ?

The solution to (x+3)/4*(x+2)/(x^2+4x+3) is (x+2)/(4(x+1))

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simplify (x+3)/4*(x+2)/(x^2+4x+3)

simplify

\frac{x + 3}{4} \cdot \frac{x + 2}{x ^{2} + 4 x + 3}

\frac{x + 2}{4 ( x + 1 )}

Solution steps

\frac{x + 3}{4} \cdot \frac{x + 2}{x ^{2} + 4 x + 3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x + 3 ) ( x + 2 )}{4 ( x ^{2} + 4 x + 3 )}

Factor

x^{2} + 4 x + 3 : (x + 1) (x + 3)

= \frac{( x + 3 ) ( x + 2 )}{4 ( x + 1 ) ( x + 3 )}

Cancel the common factor:

x + 3

= \frac{x + 2}{4 ( x + 1 )}

\frac{12}{60}

(x + \frac{1}{x})^{2}

(5 x - 2) (5 x - 2)

- 4^{0}

5 \frac{1}{3}

What is (x+3)/4*(x+2)/(x^2+4x+3) ?
The solution to (x+3)/4*(x+2)/(x^2+4x+3) is (x+2)/(4(x+1))