What is (log_{7}(32)-log_{7}(8))/(log_{7)(256)} ?

The solution to (log_{7}(32)-log_{7}(8))/(log_{7)(256)} is 1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (log_{7}(32)-log_{7}(8))/(log_{7)(256)}

simplify

\frac{lo g _{7} ( 32 ) - lo g _{7} ( 8 )}{lo g _{7} ( 256 )}

\frac{1}{4}

Decimal Notation

0.25

Solution steps

\frac{lo g _{7} ( 32 ) - lo g _{7} ( 8 )}{lo g _{7} ( 256 )}

lo g_{7} (32) - lo g_{7} (8) = 2 lo g_{7} (2)

= \frac{2 lo g _{7} ( 2 )}{lo g _{7} ( 256 )}

lo g_{7} (256) = 8 lo g_{7} (2)

= \frac{2 lo g _{7} ( 2 )}{8 lo g _{7} ( 2 )}

Cancel the common factor:

lo g_{7} (2)

= \frac{2}{8}

Cancel the numbers:

\frac{2}{8} = \frac{1}{4}

= \frac{1}{4}

28 \div 4

\frac{5}{6} + \frac{1}{3}

16 \times 16

(2 x - 7)^{3}

\frac{3 x ^{2} - 4 x - 15}{x ^{2} - 5 x + 6}

What is (log_{7}(32)-log_{7}(8))/(log_{7)(256)} ?
The solution to (log_{7}(32)-log_{7}(8))/(log_{7)(256)} is 1/4