What is expand (x+1)(x-2)(x-3) ?

The solution to expand (x+1)(x-2)(x-3) is x^3-4x^2+x+6

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expand (x+1)(x-2)(x-3)

expand

(x + 1) (x - 2) (x - 3)

x^{3} - 4 x^{2} + x + 6

Solution steps

(x + 1) (x - 2) (x - 3)

Expand

(x + 1) (x - 2) (x - 3) : (x^{2} - x - 2) (x - 3)

= (x^{2} - x - 2) (x - 3)

Distribute parentheses

= x^{2} x + x^{2} (- 3) - xx - x (- 3) - 2 x - 2 (- 3)

Simplify

x^{2} x + x^{2} (- 3) - xx - x (- 3) - 2 x - 2 (- 3) : x^{3} - 4 x^{2} + x + 6

= x^{3} - 4 x^{2} + x + 6

\frac{20}{6}

(2 a + b)^{2}

16 c^{2} - 104 c + 169

(b^{2} + 5) (- b^{2} + 7)

(x + 3) (x - 7)

What is expand (x+1)(x-2)(x-3) ?
The solution to expand (x+1)(x-2)(x-3) is x^3-4x^2+x+6