What is ((2x+1)/2)/((2x^2+7x+3)/6) ?

The solution to ((2x+1)/2)/((2x^2+7x+3)/6) is 3/(x+3)

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simplify ((2x+1)/2)/((2x^2+7x+3)/6)

simplify

\frac{\frac{2 x + 1}{2}}{\frac{2 x ^{2} + 7 x + 3}{6}}

\frac{3}{x + 3}

Solution steps

\frac{\frac{2 x + 1}{2}}{\frac{2 x ^{2} + 7 x + 3}{6}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 2 x + 1 ) \cdot 6}{2 ( 2 x ^{2} + 7 x + 3 )}

Cancel

\frac{( 2 x + 1 ) \cdot 6}{2 ( 2 x ^{2} + 7 x + 3 )} : \frac{3}{x + 3}

= \frac{3}{x + 3}

\frac{x ^{2} - x - 20}{3 x - 15}

\frac{6}{6}

\frac{4}{8}

(5 x - 2 y)^{2}

\frac{16}{36}

What is ((2x+1)/2)/((2x^2+7x+3)/6) ?
The solution to ((2x+1)/2)/((2x^2+7x+3)/6) is 3/(x+3)