What is ((2x^4y)/(4xy^2))^2 ?

The solution to ((2x^4y)/(4xy^2))^2 is (x^6)/(4y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((2x^4y)/(4xy^2))^2

simplify

(\frac{2 x ^{4} y}{4 x y ^{2}})^{2}

\frac{x ^{6}}{4 y ^{2}}

Solution steps

(\frac{2 x ^{4} y}{4 x y ^{2}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x ^{4} y ) ^{2}}{( 4 x y ^{2} ) ^{2}}

Simplify

(2 x^{4} y)^{2} : 4 x^{8} y^{2}

= \frac{4 x ^{8} y ^{2}}{( 4 x y ^{2} ) ^{2}}

Simplify

(4 x y^{2})^{2} : 16 x^{2} y^{4}

= \frac{4 x ^{8} y ^{2}}{16 x ^{2} y ^{4}}

Cancel the common factor:

4

= \frac{x ^{8} y ^{2}}{4 x ^{2} y ^{4}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{x ^{8}}{x ^{2}} = x^{8 - 2}

= \frac{y ^{2} x ^{8 - 2}}{4 y ^{4}}

Subtract the numbers:

8 - 2 = 6

= \frac{x ^{6} y ^{2}}{4 y ^{4}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{y ^{2}}{y ^{4}} = \frac{1}{y ^{4 - 2}}

= \frac{x ^{6}}{4 y ^{4 - 2}}

Subtract the numbers:

4 - 2 = 2

= \frac{x ^{6}}{4 y ^{2}}

- 3 y^{2} = 6 y + 2

\frac{3}{2} \cdot 4

- 3 z^{2} - 2 z + 6 = 0

\frac{x ^{- 1} + y ^{- 1}}{( x + y ) ^{- 1}}

- 6 x^{2} - 15 x + 9

What is ((2x^4y)/(4xy^2))^2 ?
The solution to ((2x^4y)/(4xy^2))^2 is (x^6)/(4y^2)