What is (3x^2+2x-5)+(7-3x+4x^2) ?

The solution to (3x^2+2x-5)+(7-3x+4x^2) is 7x^2-x+2

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simplify (3x^2+2x-5)+(7-3x+4x^2)

simplify

(3 x^{2} + 2 x - 5) + (7 - 3 x + 4 x^{2})

7 x^{2} - x + 2

Solution steps

(3 x^{2} + 2 x - 5) + (7 - 3 x + 4 x^{2})

Simplify

(3 x^{2} + 2 x - 5) + (7 - 3 x + 4 x^{2}) : 3 x^{2} + 2 x - 5 + 7 - 3 x + 4 x^{2}

= 3 x^{2} + 2 x - 5 + 7 - 3 x + 4 x^{2}

Group like terms

= 3 x^{2} + 4 x^{2} + 2 x - 3 x - 5 + 7

Add similar elements:

3 x^{2} + 4 x^{2} = 7 x^{2}

= 7 x^{2} + 2 x - 3 x - 5 + 7

Add similar elements:

2 x - 3 x = - x

= 7 x^{2} - x - 5 + 7

Add the numbers:

- 5 + 7 = 2

= 7 x^{2} - x + 2

- 1 6^{\frac{1}{4}}

\frac{4}{d ^{2}} + \frac{5}{d} + 1

(9 x + 5) + (- 2 x^{2} + 10 x)

\frac{23}{2}

lo g_{12} (12)

What is (3x^2+2x-5)+(7-3x+4x^2) ?
The solution to (3x^2+2x-5)+(7-3x+4x^2) is 7x^2-x+2