What is (x^2-3x)/(x^2+3x) ?

The solution to (x^2-3x)/(x^2+3x) is (x-3)/(x+3)

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simplify (x^2-3x)/(x^2+3x)

simplify

\frac{x ^{2} - 3 x}{x ^{2} + 3 x}

\frac{x - 3}{x + 3}

Solution steps

\frac{x ^{2} - 3 x}{x ^{2} + 3 x}

Factor

x^{2} - 3 x : x (x - 3)

= \frac{x ( x - 3 )}{x ^{2} + 3 x}

Factor

x^{2} + 3 x : x (x + 3)

= \frac{x ( x - 3 )}{x ( x + 3 )}

Cancel the common factor:

x

= \frac{x - 3}{x + 3}

(4 x^{2} + 8) + (- 8 x^{2} - 5 x + 2)

\frac{x ^{3} + 5 x ^{2} - 17 x - 21}{( x + 1 )}

(x^{2} + 4) (x^{2} - 6)

(- 3 x^{2} + 9 x - 9) + (- 9 x^{2} + 9 x + 3)

\frac{5 ^{7}}{5 ^{3}}