What is expand (x+1)(x-2)(x+3) ?

The solution to expand (x+1)(x-2)(x+3) is x^3+2x^2-5x-6

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expand (x+1)(x-2)(x+3)

expand

(x + 1) (x - 2) (x + 3)

x^{3} + 2 x^{2} - 5 x - 6

Solution steps

(x + 1) (x - 2) (x + 3)

Expand

(x + 1) (x - 2) (x + 3) : (x^{2} - x - 2) (x + 3)

= (x^{2} - x - 2) (x + 3)

Distribute parentheses

= x^{2} x + x^{2} \cdot 3 - xx - x \cdot 3 - 2 x - 2 \cdot 3

Simplify

x^{2} x + x^{2} \cdot 3 - xx - x \cdot 3 - 2 x - 2 \cdot 3 : x^{3} + 2 x^{2} - 5 x - 6

= x^{3} + 2 x^{2} - 5 x - 6

lo g_{\frac{1}{6}} (36)

(n + 8) + (n - 12)

(a^{x} + b^{x + 1})^{2}

(x - 2) (x + 6)

\frac{40}{5}

What is expand (x+1)(x-2)(x+3) ?
The solution to expand (x+1)(x-2)(x+3) is x^3+2x^2-5x-6