What is (3-2x+2x^2)-(4x-5+3x^2) ?

The solution to (3-2x+2x^2)-(4x-5+3x^2) is -x^2-6x+8

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simplify (3-2x+2x^2)-(4x-5+3x^2)

simplify

(3 - 2 x + 2 x^{2}) - (4 x - 5 + 3 x^{2})

- x^{2} - 6 x + 8

Solution steps

(3 - 2 x + 2 x^{2}) - (4 x - 5 + 3 x^{2})

Apply rule:

(a) = a

(3 - 2 x + 2 x^{2}) = 3 - 2 x + 2 x^{2}

= 3 - 2 x + 2 x^{2} - (4 x - 5 + 3 x^{2})

Apply the distributive law:

- (a - b) = - a + b

- (4 x - 5 + 3 x^{2}) = - 4 x + 5 - 3 x^{2}

= 3 - 2 x + 2 x^{2} - 4 x + 5 - 3 x^{2}

Group like terms

= 2 x^{2} - 3 x^{2} - 2 x - 4 x + 3 + 5

Add similar elements:

2 x^{2} - 3 x^{2} = - x^{2}

= - x^{2} - 2 x - 4 x + 3 + 5

Add similar elements:

- 2 x - 4 x = - 6 x

= - x^{2} - 6 x + 3 + 5

Add the numbers:

3 + 5 = 8

= - x^{2} - 6 x + 8

(6 x^{2} - 5 x) - (10 x^{2} + 8 x - 8)

\frac{36}{6}

(x + 8) (x - 3)

lo g_{9} (2)

ln (x^{x})

What is (3-2x+2x^2)-(4x-5+3x^2) ?
The solution to (3-2x+2x^2)-(4x-5+3x^2) is -x^2-6x+8