What are the solutions to the equation x^2+6x=-3 ?

The solutions to the equation x^2+6x=-3 are x=-3+sqrt(6),x=-3-sqrt(6)

Find the zeros of x^2+6x=-3

The zeros of x^2+6x=-3 are x=-3+sqrt(6),x=-3-sqrt(6)

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x^{2} + 6 x = - 3

x = - 3 + 6, x = - 3 - 6

Decimal Notation

x = - 0.55051 \dots, x = - 5.44948 \dots

Solution steps

x^{2} + 6 x = - 3

Move

3

to the left side

x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 3 = 26

x_{1, 2} = \frac{- 6 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 6}{2 \cdot 1}

x = \frac{- 6 + 2 6}{2 \cdot 1} : - 3 + 6

x = \frac{- 6 - 2 6}{2 \cdot 1} : - 3 - 6

The solutions to the quadratic equation are:

x = - 3 + 6, x = - 3 - 6

\frac{1}{3} x = \frac{7}{3}

\frac{a - 1}{6 a + 6} - \frac{a + 3}{9 a + 9}

- \frac{9}{8} (2)^{3}

- 2 x - 3 = 0

0.3 \cdot 10 + \frac{10}{5}

What are the solutions to the equation x^2+6x=-3 ?
The solutions to the equation x^2+6x=-3 are x=-3+sqrt(6),x=-3-sqrt(6)
Find the zeros of x^2+6x=-3
The zeros of x^2+6x=-3 are x=-3+sqrt(6),x=-3-sqrt(6)