What is (x^2+2x-8)/(x^2-4) ?

The solution to (x^2+2x-8)/(x^2-4) is (x+4)/(x+2)

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simplify (x^2+2x-8)/(x^2-4)

simplify

\frac{x ^{2} + 2 x - 8}{x ^{2} - 4}

\frac{x + 4}{x + 2}

Solution steps

\frac{x ^{2} + 2 x - 8}{x ^{2} - 4}

Factor

x^{2} + 2 x - 8 : (x - 2) (x + 4)

= \frac{( x - 2 ) ( x + 4 )}{x ^{2} - 4}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x - 2 ) ( x + 4 )}{( x + 2 ) ( x - 2 )}

Cancel the common factor:

x - 2

= \frac{x + 4}{x + 2}

4 \times 7

\frac{16}{30}

(\frac{5}{3} - m^{3})^{2}

lo g_{3} (x^{2})

(x + 3) (x - 8)