What is 3x-8+2x+15<= 9x-23+2x+12 ?

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3x-8+2x+15<= 9x-23+2x+12

3 x - 8 + 2 x + 15 \leq 9 x - 23 + 2 x + 12

x \geq 3

Interval Notation

[3, \infty)

Solution steps

3 x - 8 + 2 x + 15 \leq 9 x - 23 + 2 x + 12

Subtract

2 x

from both sides

3 x - 8 + 2 x + 15 - 2 x \leq 9 x - 23 + 2 x + 12 - 2 x

Simplify

3 x - 8 + 15 \leq 9 x - 23 + 12

Add/Subtract the numbers:

- 8 + 15 = 7

3 x + 7 \leq 9 x - 23 + 12

Add/Subtract the numbers:

- 23 + 12 = - 11

3 x + 7 \leq 9 x - 11

Move

7

to the right side

3 x \leq 9 x - 18

Move

9 x

to the left side

- 6 x \leq - 18

Multiply both sides by

- 1

6 x \geq 18

Divide both sides by

6

x \geq 3

2 ∣ 3 x + 1 ∣ = 20

(x - 12) 4 = 36

e^{- 0.5}

3 x^{2} - 6 x - 3

16 k^{2} - 24 k + 8

What is 3x-8+2x+15<= 9x-23+2x+12 ?
The solution to 3x-8+2x+15<= 9x-23+2x+12 is x>= 3