What is 2^{2log_{2}(3)+2log_{2}(5)} ?

The solution to 2^{2log_{2}(3)+2log_{2}(5)} is 225

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simplify 2^{2log_{2}(3)+2log_{2}(5)}

simplify

2^{2 l o g_{2} (3) + 2 l o g_{2} (5)}

225

Solution steps

2^{2 l o g_{2} (3) + 2 l o g_{2} (5)}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

2^{2 l o g_{2} (3) + 2 l o g_{2} (5)} = 2^{2 l o g_{2} (3)} \cdot 2^{2 l o g_{2} (5)}

= 2^{2 l o g_{2} (3)} \cdot 2^{2 l o g_{2} (5)}

2^{2 l o g_{2} (3)} = 9

2^{2 l o g_{2} (5)} = 25

= 9 \cdot 25

Multiply the numbers:

9 \cdot 25 = 225

= 225

\frac{40}{9}

(b + 10)^{3}

\frac{1}{3}

(x - 5) 2

(8 - 3 a^{2}) (2 a^{2} + 6)

What is 2^{2log_{2}(3)+2log_{2}(5)} ?
The solution to 2^{2log_{2}(3)+2log_{2}(5)} is 225