What is (7x^2-2)-(2x^2-5x+3) ?

The solution to (7x^2-2)-(2x^2-5x+3) is 5x^2+5x-5

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simplify (7x^2-2)-(2x^2-5x+3)

simplify

(7 x^{2} - 2) - (2 x^{2} - 5 x + 3)

5 x^{2} + 5 x - 5

Solution steps

(7 x^{2} - 2) - (2 x^{2} - 5 x + 3)

Apply rule:

(a) = a

(7 x^{2} - 2) = 7 x^{2} - 2

= 7 x^{2} - 2 - (2 x^{2} - 5 x + 3)

Apply the distributive law:

- (a - b) = - a + b

- (2 x^{2} - 5 x + 3) = - 2 x^{2} + 5 x - 3

= 7 x^{2} - 2 - 2 x^{2} + 5 x - 3

Group like terms

= 7 x^{2} - 2 x^{2} + 5 x - 2 - 3

Add similar elements:

7 x^{2} - 2 x^{2} = 5 x^{2}

= 5 x^{2} + 5 x - 2 - 3

Subtract the numbers:

- 2 - 3 = - 5

= 5 x^{2} + 5 x - 5

2 \cdot (- 5)

\frac{16}{7}

(x - 5) (x + 6)

(- 6 x^{2} - x) - (- 4 x^{2} + 10 x - 1)

(8 p - 2) (6 p + 2)

What is (7x^2-2)-(2x^2-5x+3) ?
The solution to (7x^2-2)-(2x^2-5x+3) is 5x^2+5x-5