What is factor 4D^2+24D+35 ?

The solution to factor 4D^2+24D+35 is (2D+5)(2D+7)

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factor 4D^2+24D+35

factor

4 D^{2} + 24 D + 35

(2 D + 5) (2 D + 7)

Solution steps

4 D^{2} + 24 D + 35

Break the expression into groups

= (4 D^{2} + 10 D) + (14 D + 35)

Factor out

2 D

from

4 D^{2} + 10 D : 2 D (2 D + 5)

Factor out

7

from

14 D + 35 : 7 (2 D + 5)

= 2 D (2 D + 5) + 7 (2 D + 5)

Factor out common term

2 D + 5

= (2 D + 5) (2 D + 7)

(1 - x)^{5}

\frac{2 x + 6}{4 x - 12}

- 4^{- 3}

(7 a^{2} b^{3} + 5 x^{4})^{2}

(11 - 7 i) + (2 - 5 i)